-7x^2+x-14=-9-8x^2+9x

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Solution for -7x^2+x-14=-9-8x^2+9x equation:



-7x^2+x-14=-9-8x^2+9x
We move all terms to the left:
-7x^2+x-14-(-9-8x^2+9x)=0
We get rid of parentheses
-7x^2+8x^2-9x+x+9-14=0
We add all the numbers together, and all the variables
x^2-8x-5=0
a = 1; b = -8; c = -5;
Δ = b2-4ac
Δ = -82-4·1·(-5)
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{21}}{2*1}=\frac{8-2\sqrt{21}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{21}}{2*1}=\frac{8+2\sqrt{21}}{2} $

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